Данный перевод возможен двумя способами: прямой перевод и через десятичную систему.
Сначала выполним прямой перевод.
Выполним прямой перевод из шестнадцатиричной в двоичную вот так:
A67B787F16 = A 6 7 B 7 8 7 F = A(=1010) 6(=0110) 7(=0111) B(=1011) 7(=0111) 8(=1000) 7(=0111) F(=1111) = 101001100111101101111000011111112
Окончательный ответ: A67B787F16 = 101001100111101101111000011111112
Теперь выполним перевод через десятичную систему счисления.
Выполним перевод в десятичную систему счисления вот так:
10∙167+6∙166+7∙165+11∙164+7∙163+8∙162+7∙161+15∙160 = 10∙268435456+6∙16777216+7∙1048576+11∙65536+7∙4096+8∙256+7∙16+15∙1 = 2684354560+100663296+7340032+720896+28672+2048+112+15 = 279310963110
Получилось: A67B787F16 =279310963110
Переведем число 279310963110 в двоичное вот так:
Целая часть числа находится делением на основание новой системы счисления:
2793109631 | 2 | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |
-2793109630 | 1396554815 | 2 | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |
1 | -1396554814 | 698277407 | 2 | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |
| 1 | -698277406 | 349138703 | 2 | | | | | | | | | | | | | | | | | | | | | | | | | | | | |
| | 1 | -349138702 | 174569351 | 2 | | | | | | | | | | | | | | | | | | | | | | | | | | | |
| | | 1 | -174569350 | 87284675 | 2 | | | | | | | | | | | | | | | | | | | | | | | | | | |
| | | | 1 | -87284674 | 43642337 | 2 | | | | | | | | | | | | | | | | | | | | | | | | | |
| | | | | 1 | -43642336 | 21821168 | 2 | | | | | | | | | | | | | | | | | | | | | | | | |
| | | | | | 1 | -21821168 | 10910584 | 2 | | | | | | | | | | | | | | | | | | | | | | | |
| | | | | | | 0 | -10910584 | 5455292 | 2 | | | | | | | | | | | | | | | | | | | | | | |
| | | | | | | | 0 | -5455292 | 2727646 | 2 | | | | | | | | | | | | | | | | | | | | | |
| | | | | | | | | 0 | -2727646 | 1363823 | 2 | | | | | | | | | | | | | | | | | | | | |
| | | | | | | | | | 0 | -1363822 | 681911 | 2 | | | | | | | | | | | | | | | | | | | |
| | | | | | | | | | | 1 | -681910 | 340955 | 2 | | | | | | | | | | | | | | | | | | |
| | | | | | | | | | | | 1 | -340954 | 170477 | 2 | | | | | | | | | | | | | | | | | |
| | | | | | | | | | | | | 1 | -170476 | 85238 | 2 | | | | | | | | | | | | | | | | |
| | | | | | | | | | | | | | 1 | -85238 | 42619 | 2 | | | | | | | | | | | | | | | |
| | | | | | | | | | | | | | | 0 | -42618 | 21309 | 2 | | | | | | | | | | | | | | |
| | | | | | | | | | | | | | | | 1 | -21308 | 10654 | 2 | | | | | | | | | | | | | |
| | | | | | | | | | | | | | | | | 1 | -10654 | 5327 | 2 | | | | | | | | | | | | |
| | | | | | | | | | | | | | | | | | 0 | -5326 | 2663 | 2 | | | | | | | | | | | |
| | | | | | | | | | | | | | | | | | | 1 | -2662 | 1331 | 2 | | | | | | | | | | |
| | | | | | | | | | | | | | | | | | | | 1 | -1330 | 665 | 2 | | | | | | | | | |
| | | | | | | | | | | | | | | | | | | | | 1 | -664 | 332 | 2 | | | | | | | | |
| | | | | | | | | | | | | | | | | | | | | | 1 | -332 | 166 | 2 | | | | | | | |
| | | | | | | | | | | | | | | | | | | | | | | 0 | -166 | 83 | 2 | | | | | | |
| | | | | | | | | | | | | | | | | | | | | | | | 0 | -82 | 41 | 2 | | | | | |
| | | | | | | | | | | | | | | | | | | | | | | | | 1 | -40 | 20 | 2 | | | | |
| | | | | | | | | | | | | | | | | | | | | | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | | | | | | | | | | | | | | | | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | | | | | | | | | | | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | | | | | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | | | | | | | | | | | | | | | | | 0 | | |
 |
В результате преобразования получилось:
279310963110 = 101001100111101101111000011111112
Окончательный ответ: A67B787F16 = 101001100111101101111000011111112